Видео с ютуба (Cos A - Sin A 1)

Q) cos(sin^(−1) 3/5+sin^(−1) 5/13+sin^(−1) 33/65)JEE MAINS 2025 ( 28 Jan #class11trigonometry

Q) cos(sin^(−1) 3/5+sin^(−1) 5/13+sin^(−1) 33/65)JEE MAINS 2025 ( 28 Jan #class11trigonometry
(cosec(A) - sin A)(sec(A) - cos A) = 1/(tan A + cot A) || class 10th maths By Jeevan sir

(cosec(A) - sin A)(sec(A) - cos A) = 1/(tan A + cot A) || class 10th maths By Jeevan sir

(sin⁡4x−cos⁡4x)/(sin⁡2x−cos⁡2x) dapat disederhanakan dan membuktikan 1/sin x−sin x = cos x ⋅ cot x

(sin⁡4x−cos⁡4x)/(sin⁡2x−cos⁡2x) dapat disederhanakan dan membuktikan 1/sin x−sin x = cos x ⋅ cot x
sin -1[cos(43 π/5)] 2) cos -1[cos(-680)]

sin -1[cos(43 π/5)] 2) cos -1[cos(-680)]
sin^-1 [sin(13π/6 )] + cos^-1 [cos (π/3) ] +tan^-1 √(3) #cbsepyq #maths #cbse #cbseboard

sin^-1 [sin(13π/6 )] + cos^-1 [cos (π/3) ] +tan^-1 √(3) #cbsepyq #maths #cbse #cbseboard
[11] SOAL LIMIT TAK HINGGA TRIGONOMETRI lim sin 3/x / (1-cos 2/x) x^2 sin 1/x [BAHAS TUNTAS‼️]

[11] SOAL LIMIT TAK HINGGA TRIGONOMETRI lim sin 3/x / (1-cos 2/x) x^2 sin 1/x [BAHAS TUNTAS‼️]
Sin²θ + Cos²θ = 1 #синускосинус #тригонометрическиетождества #тригонометрия10класс #класс10

Sin²θ + Cos²θ = 1 #синускосинус #тригонометрическиетождества #тригонометрия10класс #класс10

"Prove that: sin A · cos 2A = 1/4 sin 4A · sec A | Trigonometry Proof" | Class 10 maths
The value of sin and cos will change but the answer will always be 1😱 #shorts #@Educationalvideo1602

The value of sin and cos will change but the answer will always be 1😱 #shorts #@Educationalvideo1602
sin^2a +cos^2b = 1

sin^2a +cos^2b = 1
“1 Line Trick to Solve ∫ sin⁻¹(cos 3x) 🔥” #jeemain #jeeproblems #mhcet #maths #jeebatch

“1 Line Trick to Solve ∫ sin⁻¹(cos 3x) 🔥” #jeemain #jeeproblems #mhcet #maths #jeebatch
Prove Sin A/(1+cos A) = (1-cos A)/sin A

Prove Sin A/(1+cos A) = (1-cos A)/sin A
Q) If sin𝜃+cos𝜃=1/2, then 16(sin(2𝜃)+cos(4𝜃)+sin(6𝜃)) is equal to #jee #maths #jee #jee2026

Q) If sin𝜃+cos𝜃=1/2, then 16(sin(2𝜃)+cos(4𝜃)+sin(6𝜃)) is equal to #jee #maths #jee #jee2026
05 lt grade 2025 | conversions of the series cos(1/n) and 1/n sin(1/n)

05 lt grade 2025 | conversions of the series cos(1/n) and 1/n sin(1/n)
Обратные тригонометрические функции: упрощение cos(sin^-1(0)-cos^-1(1/2)) #тригонометрия

Обратные тригонометрические функции: упрощение cos(sin^-1(0)-cos^-1(1/2)) #тригонометрия
Q) If 𝑥=sin^(−1) (sin10) and 𝑦=cos^(−1) (cos10), then 𝑦−𝑥 is equal to #jee #maths #jeeproblems

Q) If 𝑥=sin^(−1) (sin10) and 𝑦=cos^(−1) (cos10), then 𝑦−𝑥 is equal to #jee #maths #jeeproblems
𝒄𝒐𝒔⁡ 𝑨−𝒔𝒊𝒏⁡ 𝑨+𝟏 /𝒄𝒐𝒔⁡ 𝑨+𝒔𝒊𝒏⁡ 𝑨−𝟏 = 𝒄𝒐𝒕⁡𝑨 + 𝒄𝒐𝒔𝒆𝒄 𝑨 | 𝒕𝒂𝒏⁡𝑨/(𝟏−𝒄𝒐𝒕𝑨)+𝒄𝒐𝒕⁡𝑨/(𝟏−𝒕𝒂𝒏⁡𝑨 )=𝟏+𝒕𝒂𝒏⁡𝑨+𝒄𝒐𝒕⁡𝑨

𝒄𝒐𝒔⁡ 𝑨−𝒔𝒊𝒏⁡ 𝑨+𝟏 /𝒄𝒐𝒔⁡ 𝑨+𝒔𝒊𝒏⁡ 𝑨−𝟏 = 𝒄𝒐𝒕⁡𝑨 + 𝒄𝒐𝒔𝒆𝒄 𝑨 | 𝒕𝒂𝒏⁡𝑨/(𝟏−𝒄𝒐𝒕𝑨)+𝒄𝒐𝒕⁡𝑨/(𝟏−𝒕𝒂𝒏⁡𝑨 )=𝟏+𝒕𝒂𝒏⁡𝑨+𝒄𝒐𝒕⁡𝑨
Q) lim_(𝑥→1/√2) (sin(cos^(−1) 𝑥)−𝑥)/(1−tan(cos^(−1) 𝑥) )#jee #jeeproblems #jee2025 #jee2026

Q) lim_(𝑥→1/√2) (sin(cos^(−1) 𝑥)−𝑥)/(1−tan(cos^(−1) 𝑥) )#jee #jeeproblems #jee2025 #jee2026
Prove (tan⁡𝐴+1)/(tan⁡𝐴−1)=(sin⁡𝐴+cos⁡𝐴)/(sin⁡𝐴−cos⁡𝐴)(tanA+1)/(tanA−1)=(sinA+cosA)/(sinA−cosA)

Prove (tan⁡𝐴+1)/(tan⁡𝐴−1)=(sin⁡𝐴+cos⁡𝐴)/(sin⁡𝐴−cos⁡𝐴)(tanA+1)/(tanA−1)=(sinA+cosA)/(sinA−cosA)
🐾 Если Cos 9α = Sin α и 9α меньше 90°, то значение tan (5α) равно: (a) 1/√3 (b) √3(c) 1(d) 0

🐾 Если Cos 9α = Sin α и 9α меньше 90°, то значение tan (5α) равно: (a) 1/√3 (b) √3(c) 1(d) 0